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From: Lewis_Evans@Playstation.sony.com
Newsgroups: scee.yaroze.freetalk.english
Subject: ANSI C code
Date: 11 Mar 1998 10:52:43 -0000
Organization: Sony Computer Entertainment Europe - 119.SS5
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From: Lewis_Evans@Playstation.sony.com
To: news@playstation.co.uk


Owing to how I learnt C (without a textbook) I've been happily
producing yaroze code that doesn't seem to work on CodeWarrior, I
assume because my code isn't ANSI standard. What precautions do I have
to take to ensure codewarrior will compile my code? I've found out
about two...

Both Net Yaroze compilers (GNU and CodeWarrior) are very close to
being fully ANSI C compliant. However, this really doesn't
sound like the cause of the trouble.

when using #define, the defined part must be in brackets, and
at the end of IF and FOR loops, it seems to not want a semicolon after
the final closing brace.

Not sure what you mean about brackets; for simple constants,
#define FALSE 0
#define TRUE 1
but for macros, yes, eg
#define abs(x) x >= 0 ? x : -x
will give problems with eg abs(y-5) and other expressions
since the expressions are just shoved into the macro and precedence
becomes tangled.

With <if> and <for>, the syntax is thus

if (expression)
     {
     // consequent action code here
     }
the <if> binds with the very next code block (eg single statement)
it finds, so
if (expression) ;
means 'if expression true, do the semicolon', ie do nothing no matter what.
<for> binds in the same way, so
for (/*conditions*/) ;
means (for .....) do nothing, since the semicolon has no effects.
     Lewis